countingwithgroupsof10 | |
left |
Simplify monomial term number 1
countingwithgroupsof10
No simplification is needed
Simplify monomial term number 2
left
No simplification is needed
left) | |
No GCF exists, so we continue,
the constants stay the same in the numerator and denominator.
We only have a c term in the numerator,
so we leave this where it is
We only have a e term in the denominator,
so we leave this where it is
We only have a f term in the numerator,
so we leave this where it is
We only have a f term in the denominator,
so we leave this where it is
We only have a f10 term in the numerator,
so we leave this where it is
We have the same g1 term in the numerator and denominator,
so they cancel each other out
We only have a h term in the numerator,
so we leave this where it is
We have the same i1 term in the numerator and denominator,
so they cancel each other out
We only have a l term in the denominator,
so we leave this where it is
We have the same n1 term in the numerator and denominator,
so they cancel each other out
We have the same o1 term in the numerator and denominator,
so they cancel each other out
We only have a p term in the numerator,
so we leave this where it is
We only have a r term in the numerator,
so we leave this where it is
We only have a s term in the numerator,
so we leave this where it is
We have the same t1 term in the numerator and denominator,
so they cancel each other out
We have the same u1 term in the numerator and denominator,
so they cancel each other out
We only have a w term in the numerator,
so we leave this where it is
countingwithgroupsof10 | |
left |
= |
cff10hprsw |
e1fl |